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SO2

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Ca (s) +CL2 (g) → CaCl2 (aq)
2 Fe (s) +O2 (g) → 2FeO (s)
4 AI (s) + 3 O2 (g) → 2 Al2O3 (s)

HNo3 → H2o + ?
2HN03 → H2O + N2O5

2 H3PO4 → H2O + H4P2O7
3 H3PO4 → 3H2O + P2O5

HNO3 (aq) + NaOH (aq) → NanO3 (aq) + H2O (l)

1 HCL + 1 LiOH → 1 H2O (l) + 1 LiCl (aq)
2 HClO3 + Ca(OH)2 (aq) → H2O (l) + Ca(ClO3)2 (aq)
H2SO4 (aq) + 2 NaOH (aq) → 2 H2O (l) + Na2SO4 (aq)

1 HNO3 (aq) + 1 NaHCO3 (aq) → 1 H2O (l) + 1 CO2 (g) + 1 NaNO3 (aq)

Unit 2 pretest

$\ce B a C L 2 (a q) + K 2 SO 4 (a q) - > 1 B a SO 4 (s) + 2 K C L (a q)$
A reaction only happens if One has a higher reactivity than another… right? (+ one product is non aq)
$\ce M g O (s) + H_{2} O (l) - > M g (O H)_{2} (s)$
$\ce C u (s) + L i N O_{3} (a q) - > C u N O_{3} (a q)$ NR
$\ce 2 K (s) + 2 H C L (a q) \to 2 K C L (a q) + H_{2} (g)$
$\ce B e CO 3 (s) + 2 H C L (a q) - > B e Cl 2 (a q) + H 2 O (l) + CO 2 (g)$
$\ce 2 N a O H (a q) + H 2 CO 3 (a q) - > 2 H 2 O (l) + N a 2 CO 3 (s)$
$\ce 2 L i (s) + H 2 O (l) - > L i 2 O (s) + H 2 (g)$
$\ce 2 M g (s) + O 2 (g) - > 2 M g O (s)$
$\ce M g SO 3 (a q) + 2 H C L (a q) - > M g C 2 L H 2 SO 3$
$\ce M g (O H) 2 (s) - > H 2 O (l) + M g O (s)$
$\ce 2 K ClO 3 (s) - > 2 K Cl (a q) + 3 O 2 (g)$
$\ce H 3 PO 4 (a q) - > H 2 O (l) + H PO 3 (s)$

$\ce N 2 O 3 + H 2 O - > 2 H NO 2 (a q)$

Molar mass: 136.14
0.065 * 0.0153 * Molar mass

0.0009945* 136.14 = 0.13539123g
(two sig figs)
… The mass remaining in the dish is 0.14g

Jason Cameron