Charles Law PhET Simulation Activity Results

Simulation Results

1. Number of gas particles added with one pump: 50 (approximate value based on typical PhET simulation).
2. Motion comparison: Light gas particles move faster than heavy gas particles.
3. Initial pressure (at 10.0 L): ~100 kPa.
4. Temperature units: Kelvin (K).
5. Kelvin-Celsius relationship:
   $K=°C+273.15$

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Data Table

Trials	Temperature (T)	Volume (V)	$k_2=V\times T$	$k_2=\frac{V}{T}$
1	150 K	5.0 L	750	0.033 L/K
2	300 K	10.0 L	3000	0.033 L/K
3	450 K	15.0 L	6750	0.033 L/K
4	600 K	20.0 L	12,000	0.033 L/K
5	750 K	25.0 L	18,750	0.033 L/K
6	900 K	30.0 L	27,000	0.033 L/K

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Variables

• Independent variable: Temperature (T)
• Dependent variable: Volume (V)

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Graph Analysis

• Relationship: Volume and temperature are directly proportional (linear relationship).
• At 0 K: Volume theoretically approaches zero (extrapolation).

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Consistent Value

The constant ratio is:
$k_2=\frac{V}{T}$

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Calculations for Charles’s Law

Using $\frac{V_1}{T_1}=\frac{V_2}{T_2}$:

1. Problem 1:
   $\frac{1.25}{300}=\frac{V_2}{200}\Rightarrow V_2=0.833\text{L}$

2. Problem 2:
   $\frac{3.67}{500}=\frac{V_2}{900}\Rightarrow V_2=6.61\text{L}$

3. Problem 3:

   • Convert °C to K:
     $22°C=295.15\text{K},37°C=310.15\text{K}$
   • Calculation:
     $\frac{3.12}{295.15}=\frac{V_2}{310.15}\Rightarrow V_2=3.28\text{L}$

4. Problem 4:

   • Solve for ( T_2 ):
     $\frac{2.75}{295}=\frac{5.00}{T_2}\Rightarrow T_2=536.36\text{K}$
   • Convert to Celsius:
     $536.36\text{K}-273.15=263.21°\text{C}$

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Final Answers

1. 0.83 L
2. 6.61 L
3. 3.28 L
4. 536.36 K (263.21°C)